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x^2+26.305x-13.621=0
a = 1; b = 26.305; c = -13.621;
Δ = b2-4ac
Δ = 26.3052-4·1·(-13.621)
Δ = 746.437025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26.305)-\sqrt{746.437025}}{2*1}=\frac{-26.305-\sqrt{746.437025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26.305)+\sqrt{746.437025}}{2*1}=\frac{-26.305+\sqrt{746.437025}}{2} $
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